$\begin {array} {1 1} (a)\;\large\frac{0.6 ( \sqrt 3-1)}{\sqrt 3} & \quad (b)\;0.6 ( \sqrt 3-1) \\ (c)\;1.2 ( \sqrt 3+1) & \quad (d)\;\large\frac{1.2 ( \sqrt 3-1)}{\sqrt 3} \end {array}$

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A is the point $x = 1.8m$

Speed at $x = 1.8m = 6m/s$ (from energy conservation)

$R = \large\frac{mv}{qB}$$ = 1.2 m$

$B$ is the point $2.4\: m$

Angle $AOD = 30^{\circ}$

Arc $OD$ is a part of a circle with radius $1.2m$

And $CD$ makes an angle of $30O$ with the horizontal

The $y$-coordinate of $D$ is $ \large\frac{1.2 ( \sqrt 3 -1.5)}{\sqrt 3}$

Simple geometric argument will get you the coordinates of $C$.

Ans : (d)

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