$\begin{array}{1,1}(a)\;m = 36.3; V.D = 22\\(b)\;40.3 ; V.D = 23.6\\(c)\;m = 46.02 ; V.D = 23.01\\(d)\;41.03 ; V.D = 24.6\end {array}$

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Volume occupied by solute at NTP = Volume of air displaced at NTP = 112mL

Since, for volatile solute we have,

$PV = \large\frac{w}{m}RT$

at NTP, P = 1 atm , T = 273K

$\Rightarrow1\times\large\frac{112}{1000} = \large\frac{0.23}{m}\times0.0821\times273$

$\therefore$ m = 46.02

$\therefore$ Vapour Density = $\large\frac{m}{2} = 23.01$

Hence answer is (c)

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