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In Victor Mayers experiment 0.23g of a volatile solute displaced air which measures 112mL at NTP .Calculate the vapour density and molecular weight of substance

$\begin{array}{1,1}(a)\;m = 36.3; V.D = 22\\(b)\;40.3 ; V.D = 23.6\\(c)\;m = 46.02 ; V.D = 23.01\\(d)\;41.03 ; V.D = 24.6\end {array}$

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Volume occupied by solute at NTP = Volume of air displaced at NTP = 112mL
Since, for volatile solute we have,
$PV = \large\frac{w}{m}RT$
at NTP, P = 1 atm , T = 273K
$\Rightarrow1\times\large\frac{112}{1000} = \large\frac{0.23}{m}\times0.0821\times273$
$\therefore$ m = 46.02
$\therefore$ Vapour Density = $\large\frac{m}{2} = 23.01$
Hence answer is (c)
answered Feb 20, 2014 by sharmaaparna1
edited Mar 18, 2014 by mosymeow_1

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