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The decreasing order of $K_{eq}$ values in HCN addition to following aldehydes is

 

$\begin{array}{1 1}(a)\;I > II > III\\(b)\;II > III > I\\(c)\;III > I > II\\(d)\;II > I > III\end{array}$

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The decreasing order of $K_{eq}$ values in HCN addition is depend upon the electron donating groups .The order of electron donating groups are -Nme > Ome > H less $e^\ominus$ donating group mitaines more HCN addition.
Hence (d) is the correct answer.
answered Feb 20, 2014 by sreemathi.v
 

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