# The bond order of individual carbon-carbon bonds is benzene is :

a) One

b) Two

c) Between one and two

d) One and two alternately

Benzene is a resonance hybrid.
$Bond\;order =\large\frac{Total\;no\;of\; bonds\;between\;two\;atoms}{Total \; no\;of\;resonating\; structure }$
$c-c$ bond order in benzene $=\large\frac{2+1}{2}$$=1.5$
$\therefore$ option is (c) between one and two
Hence c is the correct answer.