$(a)\;2.3g\qquad(b)\;0.5g\qquad(c)\;1.67g\qquad(d)\;2.1g$

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$98.4^{\large\circ}F$ can be converted to $^{\large\circ}C$ as

$\large\frac{F-32}{9} = \large\frac{C}{5}$

$\large\frac{98.4 - 32}{9} = \large\frac{C}{5}$

$C = 36.88^{\large\circ}C$ or 309.88K

Then using,

$PV = \large\frac{w}{m}RT$

$\Rightarrow\large\frac{168}{760}\times6 = \large\frac{w}{32}\times0.0821\times309.88$

$\Rightarrow$ w = 1.67g

Hence answer is (c)

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