$(a)\;121\qquad(b)\;123\qquad(c)\;221\qquad(d)\;130$

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Weight of Liquid = 148 - 50 = 98g

Volume of liquid = $\large\frac{98}{0.98}$ = 100mL = Volume of vessel

Thus a vessel of 100mL contains ideal gas at 760mm of Hg at 300K

Weight of gas = 50.5 - 50 = 0.5g

Using PV = nRT

$\large\frac{760}{760}\times\large\frac{100}{1000} = \large\frac{0.5}{m}\times0.0821\times300$

$\therefore$ Molecular weight of gas (m) = 123

Hence answer is (b)

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