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Two protons whose velocities are in the ratio $4 : 1$, move perpendicular to a uniform magnetic field, the ratio of the radii of their paths will be

$\begin {array} {1 1} (a)\;1:1 & \quad (b)\;2:1 \\ (c)\;4:1 & \quad (d)\;1:4 \end {array}$

 

1 Answer

$R = \large\frac{mv}{qB}$
$\begin{align*}R_1 = \frac{m_p \times 4v}{qB}; \; \; \; R_2 = \frac{m_p \times v}{qB} \end{align*}$
$\therefore R_1 : R_2 = 4 : 1$
Ans : (c)
answered Feb 21, 2014 by thanvigandhi_1
edited Nov 28 by priyanka.c
 

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