Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

A proton moves in a circular path perpendicular to a magnetic field. If the intensity of the field is doubled and the radius of the circular path is constant, then the kinetic energy of the particle has

$\begin {array} {1 1} (a)\;Halved & \quad (b)\;Doubled \\ (c)\;Become\: quarter & \quad (d)\;Become\: four \: times \end {array}$

 

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...