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A wire of length $\ell$ carrying a current $i$ is bent to form a circle. Its magnetic moment is

$\begin {array} {1 1} (a)\;\large\frac{\ell i^2}{\pi} & \quad (b)\;\large\frac{\ell i^2}{4\pi} \\ (c)\;\large\frac{\ell^2 i}{\pi} & \quad (d)\;\large\frac{\ell^2 i}{4\pi} \end {array}$


1 Answer

Magnetic moment $= i A$
A=$\pi R^2$
$R = \large\frac{\ell}{2 \pi}$
Ans : (d)


answered Feb 21, 2014 by thanvigandhi_1
edited Sep 19, 2014 by thagee.vedartham

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