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Which of the following acids has the smallest dissociation constant

$(a)\;CH_3CHFCOOH \\ (b)\; FCH_2CH_2COOH \\ (c)\; BrCH_2CH_2COOH \\ (d)\; CH_3CHBrCOOH $
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The least dissociated constant is for weakest acid
(ie) $BrCH_2CH_2COOH$. $Br$ is less electronegative than $F$ and $Br$ is two carbon atoms away from $-COOH$
Hence c is the correct answer.
answered Feb 21, 2014 by meena.p
 

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