$(a)\;2\times10^{36}\qquad(b)\;1.17\times10^{45}\qquad(c)\;1.96\times10^{72}\qquad(d)\;1.23\times10^{31}$

Answer : (b) $\;1.17\times10^{45}$

Explanation :

Total energy emitted / second = power (watts)

$\large\frac{\eta}{sec}=\large\frac{Power\;of\;sun\;(W)}{\large\frac{\varepsilon}{photon}}=\large\frac{I\times(4 n R^{2})\times(6000\times10^{-10})}{6.6\times10^{-34}\times3\times10^{8}} \quad \; $ (R average radius of earth's orbit)

$=1.178\times10^{45}\;.$

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