$(a)\;2\times10^{36}\qquad(b)\;1.17\times10^{45}\qquad(c)\;1.96\times10^{72}\qquad(d)\;1.23\times10^{31}$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Answer : (b) $\;1.17\times10^{45}$

Explanation :

Total energy emitted / second = power (watts)

$\large\frac{\eta}{sec}=\large\frac{Power\;of\;sun\;(W)}{\large\frac{\varepsilon}{photon}}=\large\frac{I\times(4 n R^{2})\times(6000\times10^{-10})}{6.6\times10^{-34}\times3\times10^{8}} \quad \; $ (R average radius of earth's orbit)

$=1.178\times10^{45}\;.$

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...