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Sun gives light at rate of $\;1400 Wm^{-2}\;$ of area perpendicular to direction of light . Assume $\;\lambda\;$ (sun light )= $\;6000 A^{0}\;.$ Then no.of Photons emitted from sun/sec assuming average radius of earth's orbit is $\;1.49\times10^{11} m\;$ is


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Answer : (b) $\;1.17\times10^{45}$
Explanation :
Total energy emitted / second = power (watts)
$\large\frac{\eta}{sec}=\large\frac{Power\;of\;sun\;(W)}{\large\frac{\varepsilon}{photon}}=\large\frac{I\times(4 n R^{2})\times(6000\times10^{-10})}{6.6\times10^{-34}\times3\times10^{8}} \quad \; $ (R average radius of earth's orbit)
answered Feb 21, 2014 by yamini.v

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