Browse Questions

# Consider the following reaction number of stereo isomers formed in this reaction is

$(a)\;6\qquad(b)\;4\qquad(c)\;8\qquad(d)\;16$

Above product $-CH_3$ group is anti with respect to -OH group as well as syn also possible .So total
$2^n(n=3)$
$2^3=8$
Hence (c) is the correct answer.