$(a)\;1.3m/s\qquad(b)\;0.6m/s\qquad(c)\;2.1m/s\qquad(d)\;1.8m/s$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

$U_{AV} = \sqrt{(\large\frac{8RT}{\pi m})}$

Given

$U_{AV} = 0.3m/s$ at 300K

$\therefore U_1 = 0.3 = \sqrt{(\large\frac{8R\times300}{\pi m})}$-------(1)

At T = 273+927 = 1200K

$\therefore U_2 = \sqrt{(\large\frac{8R\times1200}{\pi m})}$-------(2)

$\therefore \large\frac{U_2}{0.3} = \sqrt{(\large\frac{1200}{300})}$

$\Rightarrow U_2 = 0.6m/s$

Hence answer is (b)

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...