Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Calculate the average volume available to a molecule in a sample of nitrogen gas at STP. What is the average distance between neighbouring molecules if nitrogen molecules are spherical in nature?

$(a)\;40.4\times10^{-8}cm\qquad(b)\;41.4\times10^{-8}cm\qquad(c)\;42.4\times10^{-8}cm\qquad(d)\;44.4\times10^{-8}cm$

1 Answer

Comment
A)
Since $6.023\times10^23$ molecules of $N_2$ occupy $22400cm^3$
One molecule of $N_2$ occupies $\large\frac{22400}{6.023\times10^23} cm^3$
(or) Volume of one molecule of $N_2 = 3.73\times 10^{-20}cm^3$
Also the average distance between two molecules = 2r
and $\large\frac{4}{3}\pi r^3 = 3.72\times10^{-20}$
$r^3 = \large\frac{3.72\times10^{-20}\times3\times7}{4\times22}$
$r = 20.7\times10^{-8}cm$
Thus average distance = $2\times20.7\times10^{-8}$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\Rightarrow = 41.4\times10^{-8}cm$
Hence answer is (b)
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...