Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Calculate the average volume available to a molecule in a sample of nitrogen gas at STP. What is the average distance between neighbouring molecules if nitrogen molecules are spherical in nature?


Can you answer this question?

1 Answer

0 votes
Since $6.023\times10^23$ molecules of $N_2$ occupy $22400cm^3$
One molecule of $N_2$ occupies $\large\frac{22400}{6.023\times10^23} cm^3$
(or) Volume of one molecule of $N_2 = 3.73\times 10^{-20}cm^3$
Also the average distance between two molecules = 2r
and $\large\frac{4}{3}\pi r^3 = 3.72\times10^{-20}$
$r^3 = \large\frac{3.72\times10^{-20}\times3\times7}{4\times22}$
$r = 20.7\times10^{-8}cm$
Thus average distance = $2\times20.7\times10^{-8}$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\Rightarrow = 41.4\times10^{-8}cm$
Hence answer is (b)
answered Feb 21, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App