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The hybridisation of carbon atoms in $C-C$ single bond of $HC \equiv C-CH = CH_2$ is

$ (a) \;sp^3-sp^3 \\ (b)\;sp^2-sp^3 \\ (c)\;sp-sp^2 \\ (d)\;sp^3-sp $
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In $C \equiv C$ there is $SP$ hybridisation where as in $C=C$ it is $SP^2$ hybridisation.
So $ sp-sp^2$
Hence c is the correct answer.
answered Feb 21, 2014 by meena.p

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