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The products of combustion of an aliphatic thiol (RSH) at 298 k are

$(a)\;CO_{2(g)}, H_2O_{(g)}\;and\;SO_{2(g)} \\ (b)\;CO_{2(g)}, H_2O_{(L)}\;and\;SO_{2(g)} \\ (c)\;CO_{2(l)}, H_2O_{(l)}\;and\;SO_{2(g)} \\ (d)\;CO_{2(g)}, H_2O_{(l)}\;ad\;SO_{2(l)} $

1 Answer

$C_2H_5SH +\large\frac{9}{2}$$ O_{2(g)} \to 2 CO_{2(g)}+3H_2O_{(l)}+SO_2{(g)}$
Hence b is the correct answer.
answered Feb 21, 2014 by meena.p
 

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