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In the following groups : $I\; - OAc ; \;\; II \; -OMe ; \; III \;-OSO_2 Me\; ; (IV) \; -OSO_2 CF_3$ the order of leaving groups ability is

$ (a)\;I > II > III >IV \\ (b)\;IV > III > I >II \\ (c)\;III > II > I >IV \\ (d)\;II > III > IV >I $

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Weaker the base better is the leaving ability.
Since the conjugate acid of a weak base is stronger therefore the correct arrangement in order of decreasing acidity is $ HOSO_2CH_3 > HOSO_2Me > HOAc > HOMe$
$IV > III > I >II$
Hence b is the correct answer.
answered Feb 21, 2014 by meena.p

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