$(a)\;39.2 A^{0}\qquad(b)\;36.6 A^{0}\qquad(c)\;42.1 A^{0}\qquad(d)\;31.2 A^{0}$

Answer : (b) $\;36.6 A^{0}$

Explanation :

Position is $\;n_{1}=1 \; ---> y\quad n_{2}=\infty$

$\bigtriangleup \varepsilon=ionization\;energy=?$

$\bigtriangleup \varepsilon=13.6\times5^2\;(\large\frac{1}{1^2}-\large\frac{1}{\infty^2})=340 eV$

$\lambda=\large\frac{hC}{\bigtriangleup \varepsilon}=\large\frac{6.63\times10^{-34}\times3\times10^{8}}{340\times1.6\times10^{-19}}=36.56\times10^{-10} A^{0}\;.$

Ask Question

Tag:MathPhyChemBioOther

Take Test

...