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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Atoms
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In a transition to a state of excitation energy 10.19eV , a hydrogen atom emits a $\;4890 A^{0}\;$ photon . Then the binding energy of initial state is :

$(a)\;-1.2 eV\qquad(b)\;-2.4 eV\qquad(c)\;-0.87 eV\qquad(d)\;-3.4 eV$

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