$(a)\;5 \% \qquad(b)\;10 \% \qquad(c)\;15 \% \qquad(d)\;20 \% $

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Answer : (a) $\;5 \%$

Explanation :

Energy of a photon is first case $\;\large\frac{12400}{3000}=4.13eV$

$or\;\varepsilon_{1}=6.6\times10^{-19}J$

Rate of incident protons $\;\large\frac{P_{1}}{\varepsilon_{1}}=\large\frac{10^{-3}}{6.6\times10^{-19}}=1.52\times10^{15}\;$ per second

No.of electrons ejected = $\;\large\frac{4.8times10^{-3}}{1.6\times10^{-19}}\;$ per second

$=3\times10^{16}\;$ per second

Efficiency of photoelectron generation = $\;\large\frac{1.52\times10^{15}}{3\times10^{16}}\times100$

$=5 \% \;.$

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