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An $SN^2$ reaction at an asymmetric carbon a compound always gives,

(a) an enantiomer of the substrate

(b) a product with opposite optical rotation

(c) a mixture of diastereomers

(d) a signal stereoisomer.

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$SN^2$ reaction proceeds by inversion of configuration .
Since only one product is obtained so we cannot obtain diastereomers.
Hence d is the correct answer.
answered Feb 22, 2014 by meena.p

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