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The $Cl-C-Cl$ angle in $1,1,2,2$- tetracholoroethene and tetrachloromethane respectively will be about

$ (a)\;120^{\circ}\;and\;109.5^{\circ} \\ (b)\;90^{\circ}\;and\;109.5^{\circ} \\ (c)\;109.5^{\circ}\;and\;90^{\circ} \\ (d)\;109.5^{\circ}\;and\;120^{\circ} $

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Since tetrachloroethene is an alkene (substitute) it has $SP^2$ hybridized $C$- atoms so $Cl - C - Cl$ bond angle is $120^{\circ}$
Tetrachlorometer is an alkane (substituted ) and in it the bond angle is $109^{\circ} 28' \;(SP^3)$ hybridisation
Hence a is the correct answer.
answered Feb 22, 2014 by meena.p

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