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# The bond between carbon atom (1) and carbon atom (2) in compound $N \equiv C_{(1)} -CH_{(2)}H \equiv CH_2$ involves the hybrid as

$(a)\;SP^2\;and\;SP^2 \\ (b)\;SP^3\;and\;SP \\ (c)\;SP\;and\;SP^2 \\ (d)\;SP\;and\;SP$

Can you answer this question?

$N \equiv C$ is $SP$ hybrid.
A carbon atom bonded to a double bond $C \equiv$ is $SP^2$ hybrid.
Hence c is the correct answer.
answered Feb 22, 2014 by