$\begin{array}{1 1} =\large\frac{n(5n+1)}{2} \\=\large\frac{n(5n+6)}{2} \\=\large\frac{n(5n-7)}{2} \\ =\large\frac{n(5n+7)}{2} \end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

- Sum of $n$ terms of an $A.P.=\large\frac{n}{2}$$[l+a]$ where $a=$ first term and $l=$last term=$t_n$

Given: $k^{th}$ term $t_k=5k+1$

$\therefore\:t_n=5n+1$

$\therefore\:t_1=a\:(first\:term)=5+1=6$

We know that $s_n=\large\frac{n}{2}$$(l+a)$

$\therefore\:S_n=\large\frac{n}{2}$$(t_n+6)=\large\frac{n}{2}$$(5n+1+6)$

$=\large\frac{n(5n+7)}{2}$

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...