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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Magnetism and Matter

The force experienced by a pole of strength $100\: A-m$ at a distance of $0.2 \: m$ from a short magnet of length $10\: cm$ and pole strength $100\: A-m$ on its axial line will be

$\begin {array} {1 1} (a)\;2.5 \times 10^{-2}N & \quad (b)\;5.0 \times 10^{-2}N \\ (c)\;2.5 \times 10^{-3}N & \quad (d)\;5.0 \times 10^{-3}N \end {array}$

 

1 Answer

F = mB
$ \begin{align*}= \frac{\mu_0}{4 \pi} \times \frac{2 m' l}{x^3} \times m \end{align*}$
$\begin{align*}= \frac{10^{-7} \times 2 \times 100 \times 0.1 \times 100}{8 \times 10^{-3}} \end{align*}$
$= 2.5 \times 10^{-2} N$
answered Feb 22, 2014 by thanvigandhi_1
edited Nov 24 by priyanka.c
 

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