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Circular arc of a wire of radius R makes an angle of 3π/2 radians at the centre. If a current i flows through it, the magnetic field intensity at the centre of the circle will be

$\begin {array} {1 1} (a)\;\large\frac{3\mu_0i}{R} & \quad (b)\;\large\frac{3\mu_0i}{2R} \\ (c)\;\large\frac{3\mu_0i}{4R} & \quad (d)\;\large\frac{3\mu_0i}{8R} \end {array}$


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$ B = \large\frac{\mu_0i \theta}{4 \pi R}$ 
substituting the value of $\theta$ we get
Ans : (d)


answered Feb 22, 2014 by thanvigandhi_1
edited Sep 18, 2014 by thagee.vedartham

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