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If the $\;K_{\alpha}\;$ radiation of $\;M_{0}\;(Z=42)\;$ has a wavelength of $\;0.71 A^{0}\;$ , than the wavelength of corresponding radiation of Cu , i. e , $\;K_{\alpha}$ for Cu $\;(z=29)\;$ assuming $\;\sigma=1\;$ .


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Answer : (a) $\;1.5A^{0}$
Explanation :
According to Moseley's low
$(Z-1)^2\; \propto \nu \quad \; or \quad \; (Z-1)^2 \propto \large\frac{1}{\lambda}$
$=1.52 A^{0}\;.$
answered Feb 22, 2014 by yamini.v

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