Chat with tutor

Ask Questions, Get Answers


Calculate the percentage of free volume available in 1 mole gaseous water at 1.0atm and $100^{\large\circ}C$. Density of liquid $H_2O$ at $100^{\large\circ}C$ is 0.958 g/mL.


1 Answer

For gaseous water PV = nRT
Thus Volume occupied by 1 mole gaseous water can be derived as
T = 273 + 100 = 373 K
$V = \large\frac{nRT}{P} = \large\frac{1\times0.0821\times373}{1}$
$\;\;\;\;\;\;\;\;\;\;\; = 30.62 litre$
Also Volume of 1 mole of liquid water = $\large\frac{mass}{density}$
$ = \large\frac{18}{0.958}$
=18.79 mL
$=18.79\times10^{-3}$ litre
Thus Volume Percentage occupied by water molecules in gaseous state
= 0.0614
$\therefore \%$ of free volume = 100 - 0.0614
Hence answer is (b)
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.