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Density of a gas is found to be $5.46g/dm^3$ at $27^{\large\circ}C$ at 2 bar pressure. What will be its density at STP?

$(a)\;3g/dm^3\qquad(b)\;4g/dm^3\qquad(c)\;5g/dm^3\qquad(d)\;6g/dm^3$

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1 Answer

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Given
d(g) = 5.46 $3g/dm^3$
T = 300K
P = 2 bar
d(g) = ?
T = 273K
P = 1 bar
Since $\large\frac{d_1}{d_2} = \large\frac{P_1m_1}{RT_1}\times\large\frac{RT_2}{P_2m_2}$
($m_1 = m_2$ for same gas)
$\large\frac{5.46}{d_2} = \large\frac{2\times273}{1\times300}$
$1\times300\times5.46 = 2\times273\times d_2$
$\large\frac{300\times5.46}{2\times273} = d_2$
$d_2 = 3g/dm^3$
Hence answer is (a)
answered Feb 23, 2014 by sharmaaparna1
 

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