$(a)\;1kg\qquad(b)\;2kg\qquad(c)\;3kg\qquad(d)\;4kg$

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Volume of cylinder is constant

$P_1V = n_1RT$

$P_2V = n_2RT$

Or $\large\frac{P_1}{P_2} =\large\frac{ n_1}{n_2} = \large\frac{\large\frac{w_1}{m}}{\large\frac{w_2}{m}}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=\large\frac{w_1}{w_2}$

$\large\frac{10}{8} = \large\frac{15}{w_2}$

$w_2 = \large\frac{15\times8}{10}$

$w_2 = \large\frac{120}{10}$

$w_2 = 12kg$

$\therefore$ Gas leaked = 15-12

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=3kg$

Hence answer is (c)

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