$(a)\;1 atm\qquad(b)\;2 atm\qquad(c)\;3 atm\qquad(d)\;4 atm$

PV = nRT (or)

$\large\frac{PV}{n} = RT$

$P_1 = 8 atm$

$V_1 = 5.0 litre$ = 3.0 mole

$P_2 = ?$

$V_2 = 10 litre$

$n_2 = 1.5 mole$

Now $\large\frac{P_1V_1}{n_1} = \large\frac{P_2V_2}{n_2}$

$\large\frac{8\times5}{3} =\large\frac{P_2\times10}{1.5}$

$\large\frac{8\times5\times1.5}{10} = P_2$

$\large\frac{40\times1.5}{10\times3} = P_2$

$\large\frac{6.0}{3} = P_2$

$P_2 = 2 atm$

Hence answer is (b)

Ask Question

Tag:MathPhyChemBioOther

Take Test

...