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The number of isomers for the compound with molecular $C_2BrClFI$ is :

$ (a)\;3 \\ (b)\;4 \\ (c)\;5 \\ (d)\;6 $
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$\therefore$ There are 6 isomers for the compound with molecular formula $C_2BrClFI$
Hence d is the correct answer.
answered Feb 24, 2014 by meena.p
 

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