Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A molecule $A_2B$(mol.weight = 166.4) occupies triclinic lattice with a = 5A , b = 8A and C = 4A . If density of $AB_2$ is $5.2g cm^{-3}$. Calculate the number of molecules present in one unit cell.


Can you answer this question?

1 Answer

0 votes
Volume of unit cell = $a\times b\times c$
$= 1.6\times10^{-22}cm^3$
Mass of unit cell = $1.6\times10^{-22}\times5.2$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = 8.32\times10^{-22}g$
No of molecules in one unit cell = $\large\frac{8.32\times10^{-22}\times6\times10^{23}}{166.4}$
Hence answer is (c)
answered Feb 24, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App