$(a)\;1\qquad(b)\;2\qquad(c)\;3\qquad(d)\;4$

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Volume of unit cell = $a\times b\times c$

$=5\times10^{-8}\times8\times10^{-8}\times4\times10^{-8}$

$= 1.6\times10^{-22}cm^3$

Mass of unit cell = $1.6\times10^{-22}\times5.2$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = 8.32\times10^{-22}g$

No of molecules in one unit cell = $\large\frac{8.32\times10^{-22}\times6\times10^{23}}{166.4}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=3$

Hence answer is (c)

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