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The correct acidity order of the following is :

$ (a)\;III > IV > II > I \\ (b)\;IV > III > I > II \\ (c)\;III > II > I > IV \\ (d)\;II > III > IV > I $
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in general, acids have greater tendency to loose $H^+$ compared to alcohols.
Out of III and IV , III is stronger acid tahn $IV$ due to the presence of $CH_3$ (+I effect) which makes the release of proton difficult from the latter.
Out of I and II ,II is a stronger acid due to presence of Cl(-I effect) which facilitates the release of proton than by (I).
Hence the order is $ III > IV > II > I$
Hence a is the correct answer.
answered Feb 24, 2014 by meena.p

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