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The weight based ratio of $\;U^{238}\;$ and $\;Pb^{226}\;$ in a sample of rock is 413 . if the half life of $\;u^{238}\;$ is $\;4.5 \times10^{9}\;years \;,$ then age of rock is

$(a)\;9 \times10^{9} years \qquad(b)\;6.3 \times10^{9} years \qquad(c)\;3.78\times10^{9} years \qquad(d)\;None$

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Answer : (c) $\;3.78 \times10^{9} years $
Explanation :
Let initial no.of U- atoms = $\;N_{0}$
After time t , (age of rock ) , Let no.of atoms remaining decayed = N
$\large\frac{238 N}{26 (N_{0}-N)}=\large\frac{4}{3}$
$t=\large\frac{\large\frac{T log N_{0}}{N}}{log 2}=\large\frac{4.5 \times10^{9}\times log 1.79}{0.301}$
$=3.78\times 10^{9} years $
answered Feb 24, 2014 by yamini.v

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