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What percent $T_1$ is of $T_2$ for a heat engine whose efficiency is 10%?

(a) 92%
(b) 10%
(c) 90%
(d) 100%

1 Answer

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  • Efficiency of a heat engine, $\eta = 1 - \frac{T_1}{T_2}$
Answer: 90%
Since, efficiency of a heat engine, $\eta = 1 - \frac{T_1}{T_2}$
Given, $\eta$ = 10%
$\frac{T_1}{T_2} = 1-\eta$ = 1 - 0.10 = 0.90 = 90%
$\therefore T_1 = 90$% $T_2$
answered Feb 24, 2014 by mosymeow_1
 

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