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Williamson ether systhesis for tert-butyl methyl ether is

$\begin{array}{1 1}(a)\;(CH_3)_3C-O^{\ominus} k^{\oplus}+H_3C-Br\rightarrow product\\(b)\;CH_3O^{\oplus} Na^{\oplus}+(CH_3)_3C-Br\rightarrow product\\(c)\;(a)\;and\;(b)\\(d)\;None\end{array}$

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This type of elimination is a dominant reaction of tetrary alkyl halide in the presence of a strong base.So does not occur the tert methyl ether.
Hence (a) is the correct answer.
answered Feb 25, 2014 by sreemathi.v

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