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The following ether,when treated with HBr produces

$\begin{array}{1 1} a \\ b \\ c \\ d \end{array}$

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A diakyl ether yields initially an alkyl halide and alcohol.The alcohol may react further to form second mole of alkyl halide.
Hence (a) is the correct answer.
answered Feb 25, 2014 by sreemathi.v
 

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