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# What are the resulting products of the reaction below?

The bond between $O-CH_3$ is weaker than the bond between $O-C_6H_5$ because the carbon of phenyl group is $SP^2$ hybridised and there is a partial double bond character.Therefore the attack by $Br^{\ominus}$ ion breakes $O-CH_3$ bond to form $CH_3Br$ and phenol.
Hence (d) is the correct answer.