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A unit cell of Nacl has four formula units. The edge length of unit cell is 0.564. The density of Nacl is

$(a)\;2.16g/cm^3\qquad(b)\;4.32g/cm^3\qquad(c)\;0.216g/cm^3\qquad(d)\;21.6g/cm^3$

1 Answer

Density = $\large\frac{n\times at.wt}{N_A \times a^3}$
$=\large\frac{4\times58.5}{6.023\times10^{23}\times(5.64\times10^{-8})^3}$
$ = 2.16 g/cm^3$
Hence answer is (a)
answered Feb 25, 2014 by sharmaaparna1
 

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