$(a)\;1\qquad(b)\;\large\frac{1}{4}\qquad(c)\;\large\frac{1}{2}\qquad(d)\;2$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Answer : (c) $\;\large\frac{1}{2}$

Explanation :

When a charged particle of charge q , mass m enters perpendicularly to magnetic induction B of a magnetic field , it will experience a magnetic force F=$q\;(\overrightarrow{V}\times\overrightarrow{B})$

$=qVB sin 90=qVB$

That provide a centripetal acceleration $\;\large\frac{V^{2}}{r}$

$rVB=\large\frac{mV^2}{r} \quad \; mV=qBr$

The de-Broglie wavelength

$\lambda=\large\frac{h}{mV}=\large\frac{h}{qBr}$

$\large\frac{\lambda_{\alpha-particle}}{\lambda_{photon}}=\large\frac{q_{P} r_{P}}{q_{\alpha}r_{\alpha}}$

Since $\;\large\frac{r_{\alpha}}{r_{P}}=I\;$ and $\;\large\frac{q_{\alpha}}{q_{P}}=2$

$\large\frac{\lambda_{\alpha}}{\lambda_{P}}=\large\frac{1}{2}\;.$

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...