$(a)\;1.259\qquad(b)\;2\qquad(c)\;\large\frac{8}{\sqrt6}\qquad(d)\;\large\frac{16}{3\sqrt6}$

$\rho_1 = \large\frac{4\times at.wt}{N_A \times a_1^3}$

$\rho_2 = \large\frac{2\times at.wt}{N_A \times a_2^3}$

$\large\frac{\rho_1}{\rho_2} = \large\frac{4}{2}\times \large\frac{a_2^3}{a_1^3}$

$=\large\frac{4}{2}\times\large\frac{(3.0\times10^{-8})^3}{(3.5\times10^{-8})^3}$

=1.259

Hence answer is (a)

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