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The treatment of $LiAlH_4$ with the below one leads to

$\begin{array}{1 1} a \\ b \\ c \\ d \end{array}$

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$LiAlH_4$ react with ester acids,amides,acid halides,anhydride will give alchols.(phthalic anhydride)
Hence (a) is the correct answer.
answered Feb 26, 2014 by sreemathi.v
 

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