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An ester (A) with molecular formula $C_9H_{10}O_2$ was treated with excess of $CH_3MgBr$ and the compound so formed was treated with conc.$H_2SO_4$ to form olefin (B).Ozonolysis of B gave ketone with formula $C_8H_8O$ with shows iodoform test positive.The structure of A is

$\begin{array}{1 1}(A)\;C_6H_5COOC_2H_5&(B)\;CH_3CO-C_6H_4-OCH_3\\(C)\;C_6H_5-OOC-C_2H_5&(D)\;\text{Above all}\end{array}$

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A-B ester with molecular formula $C_9H_{10}O_2$
Hence (a) is the correct answer.
answered Feb 26, 2014 by sreemathi.v

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