$(a)\;23\qquad(b)\;25\qquad(c)\;24\qquad(d)\;26$

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Answer : (b) 25

Explanation :

The radius of first Bohr orbit for hydrogen is :

$r_{1}=\large\frac{\varepsilon_{0}h^2}{\pi m_{e}e^2}$

For $\;r_{n}\;$ ($\;mu\;$-mesonic atom) = $\;r_{1}\;$ (hydrogen atom) ,

We have

$\large\frac{\varepsilon_{0} n^2 h^2}{624 \pi m_{e} e^2}=\large\frac{\varepsilon_{0} h^2}{n m_{e} e^2}$

$n^2=624 \qquad \; n=25\;.$

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