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In the following compounds the order of acid strength is


$\begin{array}{1 1}(a)\;(I) < (II) < (III)&(b)\;(II) < (I) < (III)\\(c)\;(III) < (II) < (I)&(d)\;(III) < (II) < (I)\end{array}$

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$e^{\ominus}$ releasing group $(NH_2)$ makes phenol less acidic while electron with drawing of group makes more acidic.The correct order of acid strength is (II) < (I) < (III)
Hence (b) is the correct answer.
answered Feb 26, 2014 by sreemathi.v
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