$\begin{array}{1 1}\large\frac{1-(A)^n}{1-a} \\ \large\frac{1-(-a)^n}{1+a} \\\large\frac{1-(-a)^n}{1-a} \\ \large\frac{1+(-a)^n}{1+a} \\ \large\frac{1+(-a)^n}{1+a} \end{array} $

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