Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Sequences and Series
0 votes

Find the sum of $n$ terms of the G,P, $x^2,x^4,x^6...........$ in terms of $x$

$\begin{array}{1 1} x^4 \large\frac{1-x^{2n}}{1-x^2} \\ x^2 \large\frac{1-x^{n}}{1-x^2} \\x^2 \large\frac{1-x^{2n}}{1+x^{2n}} \\ x^2 \large\frac{1-x^{2n}}{1-x^2}\end{array} $

Can you answer this question?

1 Answer

0 votes
  • Sum of $n$ terms of a G.P.$=S_n=a.\large\frac{1-r^n}{1-r}$ where $a=$ first term and $r$=common ratio.
Given G.P.$=x^2,x^4,x^6.........$
In this G.P. first term$=x^2$ and common ratio$=\large\frac{x^4}{x^2}$$=x^2$
We know that the sum of $n$ terms of a G.P.$=a.\large\frac{1-r^n}{1-r}$
answered Feb 26, 2014 by rvidyagovindarajan_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App