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The stability of carbanions in the following :

is in the order of 


$(a)\;iv > ii > iii > i \\ (b)\;i > iii > ii > iv \\(c)\; i > ii > iii > iv \\ (d)\;ii > iii > iv > i $
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Higher the number of electron releasing group lower will be the stability of carbanion, and vice versa.
So the order of stability of carbanations is
$ i > ii > iii > iv$
Hence c is the correct answer.
answered Feb 26, 2014 by meena.p

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