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Q)

What would be the reagent in the below reaction

$\begin{array}{1 1}(a)\;NaOH+CHCl_3&(b)\;NaOH+CCl_4\\(c)\;NaOH+CH_2Cl_2&(d)\;\text{None}\end{array}$

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A)
This is Reimer- Tiemann reaction.If $CCl_4$ is used in place of chloroform,phenolic acid is formed.
Hence (b) is the correct answer.
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